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6. in Fig. 5.10, If Ac = Bd, Then Prove That Ab = Cd. Exercise 5.1 Chapter 5 Introduction to Euclid’s Geometry

6. In Fig. 5.10, if AC = BD, then prove that AB = CD. Chapter 5: Introduction to Euclid’s Geometry Maths Class 9 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. 6. In Fig. 5.10, if AC = BD, then prove that AB = CD. is solved by our expert teachers. You can get ncert solutions and notes for class 9 chapter 5 absolutely free. NCERT Solutions for class 9 Maths Chapter 5: Introduction to Euclid’s Geometry is very essencial for getting good marks in CBSE Board examinations

6. In Fig. 5.10, if AC = BD, then prove that AB = CD.

From the above figure  we get that
AC      = AB + BC
BD      = BC + CD
It is given that AC = BD

Plug the value of AC we get
AB + BC         = BC + CD                 … (1)
According to Euclid’s axiom,when equals are subtracted from equals, the remainders
are also equal.
Subtracting BC from both side in equation (1), we get
AB + BC − BC           = BC + CD − BC
AB       = CD
Hence proved

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